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Rocket Equation Calculator (Tsiolkovsky Delta-v)

Calculate a rocket's total velocity change (delta-v) from its initial and final mass and engine specific impulse, Δv = Isp·g₀·ln(m₀/m₁).

Delta-v (total velocity change)
2,695.7 m/s
Effective exhaust velocity
2,942 m/s
Mass ratio (m₀ ÷ m₁)
2.5
Propellant mass fraction
60%

How it works

The Tsiolkovsky rocket equation, Δv = v_e·ln(m₀/m₁), gives the total velocity change a rocket can achieve from burning all its propellant, where m₀ is the rocket's initial mass (including propellant) and m₁ is its final mass after that propellant is spent. It comes directly from conservation of momentum: each small parcel of exhaust ejected backward at the effective exhaust velocity v_e gives the ever-lighter rocket a forward momentum kick, and integrating that effect from m₀ down to m₁ produces the logarithm.

Engine performance is conventionally rated as specific impulse, Isp, in seconds — a unit-system-independent figure — rather than a raw exhaust velocity, so this calculator converts it with v_e = Isp·g₀, where g₀ = 9.80665 m/s² is standard gravity, a fixed international constant used purely as a conversion factor here, not a claim about gravity at any particular place. Because mass only ever appears in the equation as the ratio m₀/m₁, that ratio — and the propellant mass fraction (m₀−m₁)/m₀ derived from it — comes out identical whether both masses are entered in kilograms or in pounds.

The logarithm is why delta-v gets dramatically harder to add as a mission's requirements grow: reaching one more increment of Δv equal to v_e multiplies the required mass ratio by e (≈2.72) rather than just adding to it, which is the mathematical root of the rocketry maxim that most of a rocket's mass has to be propellant.

FAQ

Why does adding more delta-v get so much harder, rather than just proportionally harder?

Because the equation is Δv = v_e·ln(m₀/m₁), solving for the mass ratio gives m₀/m₁ = e^(Δv/v_e) — delta-v sits inside an exponential, not a linear term. Doubling the delta-v you need doesn't double the required propellant mass fraction, it squares the mass ratio, which is why going from, say, low Earth orbit to escaping the solar system costs so much more propellant than the numbers for each individual maneuver might suggest at a glance.

Does this account for gravity losses or air drag during an actual launch?

No — the ideal rocket equation assumes no external forces acting on the rocket at all, so the delta-v it gives is the maximum theoretical velocity change available from the propellant alone. A real launch loses additional delta-v fighting gravity and atmospheric drag on the way up, which is why real launch vehicles are designed with more total delta-v capacity than the orbital velocity they're ultimately trying to reach.

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